Brake Thermal Efficiency

Brake thermal efficiency from SFOC and fuel LCV. η_th = 3600 / (SFOC · LCV).

Engine

SFOCg/kWhFuel LCVMJ/kgHFO/VLSFO ≈ 40.5; MGO ≈ 42.7; LNG ≈ 48; methanol ≈ 19.9; hydrogen ≈ 120.

Brake thermal efficiency: 50.79%

Changing the inputs requires JavaScript. The calculator above shows its default inputs and result. The formula, symbols, and regulatory sources are shown in the Formula section below.

Formula, assumptions, and limits

\eta_{th} = \frac{3600}{\text{SFOC} \cdot \text{LCV}}

Symbol	Meaning	Unit
$SFOC$	Specific fuel oil consumption	g/kWh
$LCV$	Lower calorific value	MJ/kg
$\eta_{th}$	Brake thermal efficiency

Source: Heywood - Internal Combustion Engine Fundamentals

In short

Brake thermal efficiency from SFOC and fuel LCV.

Learn the theory Engine Performance Monitoring: PMI Systems