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Stefan–Boltzmann Radiation

Net radiative heat transfer between two grey surfaces: Q = ε·σ·A·(T₁⁴ − T₂⁴).

Heat transferRadiation
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Formula, assumptions, and limits

Q=εσA(T14T24),  σ=5.67×108Q = \varepsilon \cdot \sigma \cdot A \cdot (T_1^4 - T_2^4), \; \sigma = 5.67 \times 10^{-8}
SymbolMeaningUnit
εεEmissivity
σσStefan-Boltzmann constantW/(m²·K⁴)
AASurface area
T1,T2T_1, T_2Hot and cold surface temperaturesK
QQRadiative heat flowkW

Source: Incropera - Fundamentals of Heat and Mass Transfer

In short

Net radiative heat transfer between two grey surfaces: Q = \u03b5\u00b7\u03c3\u00b7A\u00b7(T\u2081\u2074 \u2212 T\u2082\u2074).

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